Problem: To what volume (in mL) must a 3.45 M lead(II) nitrate solution be diluted in order to make 450.0 mL of a 0.990 M solution of lead(II) nitrate?A. 129B. 109C. 101D. 56.0E. 45.0

FREE Expert Solution

We are being asked of the volume of 3.45 M lead(II) nitrate solution be diluted in order to make 450.0 mL of a 0.990 M solution of lead(II) nitrate.

When dealing with dilution we will use the following equation:

M1V1 = M2V2

M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume


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Problem Details

To what volume (in mL) must a 3.45 M lead(II) nitrate solution be diluted in order to make 450.0 mL of a 0.990 M solution of lead(II) nitrate?

A. 129
B. 109
C. 101
D. 56.0
E. 45.0

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Dilution concept. If you need more Dilution practice, you can also practice Dilution practice problems.