Provide the electron configuration for Ag+.

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Jules Bruno · Accepted Answer

We are asked to determine the electron configuration of Ag+.First, determine the ground-state electron configuration of Ag.You can determine the ground-state electron configuration of Silver (Ag) by referring to the periodic table and locating the position of Ag in the periodic table.Ground-state means that the element is in its lowest energy form (not in excited state). Ca has no charge which means that no electrons are removed or added in the atom.[readmore]You will see in the above illustration of the periodic table that Ag is in Period 5 and d block.• Before reaching Ag you will pass through the atomic orbitals 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s and 4d. •In a neutral atom:Atomic number = # of protons = # of electronsCa: atomic number = 47 → 47 protons & 47 electrons• Distribute electrons in the atomic orbitals:Recall:s orbital → can hold a maximum of 2 electronsp orbitals → can hold maximum of 6 electronsd orbitals → can hold maximum of 10 electronsf orbitals → can hold maximum of 14 electronsWrite the electron configuration from the lowest energy level to the highest energy level:Ag : 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s1Next, we consider the charge. Every + charge removes 1 electron. We have +1, so we only remove 1 electron. Remove from the highest energy level.Ag : 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s1 ANSWER: Ag+ : 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10

Problem: Provide the electron configuration for Ag+.

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Problem Details

Problem: Provide the electron configuration for Ag+.

FREE Expert Solution

Problem Details

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