🤓 Based on our data, we think this question is relevant for Professor Jackson's class at FAMU.

For this problem, we’re being asked to** determine the ****number of Fe (II) ions in 20.0 g ****FeSO**_{4}

Recall that FeSO_{4} dissociates into Fe^{2+} and SO_{4}^{2-} in the reaction:

**FeSO _{4} → Fe^{2+} + SO_{4}**

The reaction tells us that 1 mol of FeSO_{4} gives 1 mol of Fe^{2+} ion and 1 mol of SO_{4}^{2-}

***Recall that Fe (II) is the same as Fe ^{2+}*

If we have 20.00 grams of FeSO_{4},_{ }we can find the number of ions of Fe(II) using molar mass of FeSO_{4}, and stoichiometric relationship from the balanced equation, and Avogadro’s number.

**Recall that Avogadro’s Number** gives us the **number of entities present in 1 mole:**** **

There are** 6.022 × 10**^{23}** Fe (II) ****ions in 1 mole Fe (II)**.

**We will do a ****molecules → moles**** calculation based on ****Avogadro's number **

How many Fe(II) ions are there in 20.00 g of FeSO _{4}?