We are asked to determine how many moles are contained in 398 mg of Krypton Kr.

To find how many moles are contained in 398 mg Kr, recall the formula for Molar Mass

$\overline{){\mathbf{Molar}}{\mathbf{}}{\mathbf{mass}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mass}\mathbf{}\mathbf{element}}{\mathbf{mole}\mathbf{}\mathbf{element}}}$

Where the **Molar mass Krypton = 83.8 grams/mole**

How many moles of Kr are contained in 398 mg of Kr?

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