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**Problem**: Calculate the molality of a 6.35 M aqueous methanol (CH3OH) solution with a density of 0.953 g/mL.A. 7.28 mB. 6.99 mC. 5.87 mD. 8.47 m

###### FREE Expert Solution

We’re being asked to calculate for the molality of a 6.35 M methanol (CH_{3}OH) solution.

When calculating for **molality**, we use the following equation:

$\overline{){\mathbf{molality}}{\mathbf{}}\left(\mathbf{m}\right){\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mol}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{solvent}}}$

We will calculate the molality of the solution using the following steps:

*Step 1**: Calculate the mass of the solute.*

*Step 2**: Calculate the mass of the solution.*

*Step 3**: Calculate the mass of the solvent (in kg).*

*Step 4**: Calculate the molality of the solution.*

**Solute → CH _{3}OH**

**Solvent → water (H _{2}O)**

###### Problem Details

Calculate the molality of a 6.35 M aqueous methanol (CH_{3}OH) solution with a density of 0.953 g/mL.

A. 7.28 m

B. 6.99 m

C. 5.87 m

D. 8.47 m

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Molality concept. You can view video lessons to learn Molality Or if you need more Molality practice, you can also practice Molality practice problems .