We can determine the largest wavelength, λmax in the Balmer series using the Balmer Equation shown below:
λmax = wavelength, m corresponding to lowest principal initial energy level, ↓ni ↑λ
R = 1.0974 x 107m-1 (Rydberg Constant) **value can be found in textbooks or online
ni = initial principal energy level
nf = final principal energy level = 2 for Balmer Series
Recall that for the Balmer series the final principal energy level nf is always = 2.
The largest wavelength, λmax will be the maximum wavelength corresponding to the lowest initial energy level, ni = 3 for a Hydrogen atom. Recall that the lowest transition releases the lowest energy, E and will occur from n = 2 to n = 3 (next energy level).
Energy, E is inversely proportional to the wavelength, λ: ↓E, ↓ni, ↑λ
What is the largest wavelength in the Balmer series?