We can determine the largest wavelength, λmax in the Balmer series using the Balmer Equation shown below:
λmax = wavelength, m corresponding to lowest principal initial energy level, ↓ni ↑λ
R = 1.0974 x 107m-1 (Rydberg Constant) **value can be found in textbooks or online
ni = initial principal energy level
nf = final principal energy level = 2 for Balmer Series
Recall that for the Balmer series the final principal energy level nf is always = 2.
The largest wavelength, λmax will be the maximum wavelength corresponding to the lowest initial energy level, ni = 3 for a Hydrogen atom. Recall that the lowest transition releases the lowest energy, E and will occur from n = 2 to n = 3 (next energy level).
Energy, E is inversely proportional to the wavelength, λ: ↓E, ↓ni, ↑λ
What is the largest wavelength in the Balmer series?
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Our tutors have indicated that to solve this problem you will need to apply the Bohr and Balmer Equations concept. If you need more Bohr and Balmer Equations practice, you can also practice Bohr and Balmer Equations practice problems.