Problem: What is the smallest wavelength in the Balmer's series?

FREE Expert Solution

We can determine the smallest wavelength, λmin in the Balmer series using the Balmer Equation shown below:



λmin  = wavelength, m at the highest initial principal energy level: ↑ni ↓λ

R = 1.0974 x 107m-1 (Rydberg Constant)      **value can be found in textbooks or online 
ni = initial principal energy level  
nf = final principal energy level = 2 for Balmer Series 

Recall that for the Balmer series the final principal energy level nf is always = 2. 

The smallest wavelength, λmin will be the minimum wavelength corresponding to the highest initial energy level, ni possible or approaching infinity,  (a symbol used to denote a super high number)  for a Hydrogen atom.

Recall that the highest transition releases the highest energy, E.

Energy, E is inversely proportional to the wavelength, λE, niλ

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What is the smallest wavelength in the Balmer's series?

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Our tutors have indicated that to solve this problem you will need to apply the Bohr and Balmer Equations concept. If you need more Bohr and Balmer Equations practice, you can also practice Bohr and Balmer Equations practice problems.