Problem: What is the smallest wavelength in the Balmer's series?

FREE Expert Solution

We can determine the smallest wavelength, λmin in the Balmer series using the Balmer Equation shown below:


1λmin=R×1nf2-1ni2

where: 

λmin  = wavelength, m at the highest initial principal energy level: ↑ni ↓λ

R = 1.0974 x 107m-1 (Rydberg Constant)      **value can be found in textbooks or online 
ni = initial principal energy level  
nf = final principal energy level = 2 for Balmer Series 


Recall that for the Balmer series the final principal energy level nf is always = 2. 

The smallest wavelength, λmin will be the minimum wavelength corresponding to the highest initial energy level, ni possible or approaching infinity,  (a symbol used to denote a super high number)  for a Hydrogen atom.

Recall that the highest transition releases the highest energy, E.

Energy, E is inversely proportional to the wavelength, λE, niλ


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What is the smallest wavelength in the Balmer's series?

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