We are asked to calculate for the change in enthalpy when three moles of methane reacts in excess oxygen.
Given the reaction:
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l) ΔH = -890 kJ
We expect that the ΔH given is the heat released (negative sign) when one mole of methane combusts in the presence of excess oxygen.
For the reaction, CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l), ΔH = -890 kJ, what will be the change in enthalpy when 3 moles of methane reacts in excess oxygen?
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