We are being asked to identify the resonance forms that describe the distribution of electrons in allyl anion (C3H5-).
We will have to draw the Lewis Structure of C3H5- first.
Step 1: Determine the central atom in this molecule.
• H is less electronegative than C but H can only make one bond
• C are the central atoms and is bonded to the H atoms
Step 2: Calculate the total number of valence electrons present.
Group Valence Electrons
C 4A 4 valence e‑ x 3
H 1A 1 valence e‑ x 5
= 17 valence e‑
-1 charge +1 e-
Total = 18 valence e-
Step 3: Draw the Lewis Structure for the molecule
• C → prefers to have a complete octet (8 e- around them)
Write resonance forms that describe the distribution of electrons in each of these molecules or ions.
the allyl ion:
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