We are being asked to identify the resonance forms that describe the distribution of electrons in bicarbonate ion, HCO3-(C is bonded to an OH group and two O atoms)
First, we will have to draw the Lewis Structure of HCO3-.
Step 1: Determine the central atom in this molecule.
• C → less electronegative atom than O → central atom
• H is less electronegative than C but H can only make one bond
Step 2: Calculate the total number of valence electrons present.
Group Valence Electrons
C 4A 4 valence e‑
O 6A 6 valence e- x 3
H 1A 1 valence e-
-1 charge +1 e-
Total = 24 valence e-
Step 3: Draw the Lewis Structure for the molecule
Write resonance forms that describe the distribution of electrons in each of these molecules or ions.
hydrogen carbonate ion, HCO3− (C is bonded to an OH group and two O atoms)
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