Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: For the following reactants, what are the products of the double displacement reaction?FeCl3(aq) + Ba(OH)2(aq) →Choose 1 answer:a. no reactionb. Fe(OH)2(s) + BaCl(aq)c. FeBa(s) + HOCl(aq)d. Fe(OH)3(s)

Problem

For the following reactants, what are the products of the double displacement reaction?

FeCl3(aq) + Ba(OH)2(aq) →

Choose 1 answer:

a. no reaction

b. Fe(OH)2(s) + BaCl(aq)

c. FeBa(s) + HOCl(aq)

d. Fe(OH)3(s) + BaCl2(aq)

Solution

We are asked to find the products of the double displacement reaction given:

FeCl3(aq) +  Ba(OH)2(aq) → 

Recall that in a double displacement reaction, the positive ions (cations) and the negative ions (anions) of the two reactants will swap or switch places.


Let us look at the components of the compounds first and get the charges of its ions through oxidation states:

FeCl3(aq)  

  • Oxidation State of Cl = -1, Total charge = 0, Fe = x

Oxidation number of Fe = 1(x) + 3(-1) = 0

Oxidation number of Fe = x - 3 = 0

Oxidation number of Fe = x = +3

Therefore, we have Fe3+ and Cl-


Ba(OH)2(aq) 

  • Oxidation State of OH = -1, Total charge = 0, Ba = x

Oxidation number of Ba = 1(x) + 2(-1) = 0

Oxidation number of Fe = x - 2 = 0

Oxidation number of Fe = x = +2

Therefore, we have Ba2+ and OH-


View the complete written solution...