We are asked to determine the volume of 0.10 M KI(aq) needed to react with 0.1 L of 0.10 M Pb(NO3)2.
Given the balanced equation:
Pb(NO3)2(aq) + 2 KI(aq) → PbI2(s) + 2 KNO3(aq)
The flow of the solution will be:
Molarity of Pb(NO3)2 (Volume of PbNO3) → Moles of Pb(NO3)2(mole to mole comparison) → Moles of KI (Molarity of KI) → Volume of KI
Consider the precipitation reaction that occurs between Pb(NO 3)2(aq) and KI(aq). When these two solutions are combined, bright yellow PbI2(s) precipitates out of solution. The balanced equation for this reaction is:
Pb(NO3)2(aq) + 2KI(aq) → PbI 2(s) + 2KNO3(aq)
If we have 0.1 L of 0.10 M Pb(NO 3)2, what volume of 0.10 M KI(aq) should we add to react with all the Pb(NO3)2 (aq)?
Choose 1 answer:
a. 0.20 L
b. 0.10 L
c. 0.40 L
d. 0.25 L
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