Balancing Redox Reactions Video Lessons

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Problem: balance ClO-(aq) + Cr(OH)4-(aq) → CrO42-(aq) + Cl -(aq) in base

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We are being asked to balance the given oxidation-reduction reaction. When balancing redox reactions under basic conditions, we will follow the following steps.

Step 1: Separate the whole reaction into two half-reactions

Step 2: Balance the non-hydrogen and non-oxygen elements first

Step 3: Balance oxygen by adding H2O to the side that needs oxygen (1 O: 1 H2O)

Step 4: Balance hydrogen by adding H+ to the side that needs hydrogen (1 H: 1 H+)

Step 5: Balance the charges: add electrons to the more positive side (or less negative side)

Step 6: Balance electrons on the two half-reactions

Step 7: Get the overall reaction by adding the two reactions.

Step 8: Balance remaining H+ by adding an equal amount of OH- ions to both sides
Step 9: H+(aq) will combine with OH-(aq) to form H2O(l)­
Step 10: Cancel out common species



Balance the redox reaction under basic condition:

ClO-(aq) + Cr(OH)4-(aq) → CrO42-(aq) + Cl-(aq)


*Before balancing the redox reaction:

ignore H+, OH-, and H2O in the starting reaction


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Problem Details

balance ClO-(aq) + Cr(OH)4-(aq) → CrO42-(aq) + Cl -(aq) in base

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Balancing Redox Reactions concept. You can view video lessons to learn Balancing Redox Reactions. Or if you need more Balancing Redox Reactions practice, you can also practice Balancing Redox Reactions practice problems.

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Based on our data, we think this problem is relevant for Professor Schraf's class at WVU.