Ch.8 - Periodic Properties of the ElementsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Is the following ion diamagnetic or paramagnetic? Ca2+

Problem

Is the following ion diamagnetic or paramagnetic? 

Ca2+

Solution

We are being asked if the species is paramagnetic or diamagnetic so we have to determine the electron configuration of Ca2+ ion

Recall that paramagnetic species have 1 or more unpaired electrons while diamagnetic contains 0 unpaired electron.

To figure that out, let’s first write the electron configuration of a neutral (uncharged) Ca atom.

Ground-state means that Calcium is in its lowest energy form (not in an excited state). 

Neutral element:       Atomic number = # protons = # of electrons

Neutral Calcium (Ca):

Atomic number = 20
• # of electrons = 20 e-

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