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Problem: For the following equation:2CH3CH3 + 7O2 → 4CO2 + 6H2OAnswer these questions:a) If 13.50g of CH3CH3 reacts with 2.00g of oxygen, which is the limiting reagent?b) If 13.50g of CH3CH3 reacts with 2.00g of oxygen, calculate the number of g of water formed?

FREE Expert Solution

We are being asked to:

(a) determine the limiting reactant when 13.50 g of CH3CHreacts with 2.00 g of O2

(b) determine the amount of water formed when 13.50 g of CH3CHreacts with 2.00 g of O2


The molar masses of the involved compounds solved below before proceeding with further calculations. 

CH3CH3           2C ×    12.01 g/mol  = 24.02 g/mol

                        6H ×    1.008 g/mol  = 6.048 g/mol

                                                SUM   = 30.068 g/mol


O2                    2O ×   16.00 g/mol  = 32.00 g/mol

                                                SUM   = 32.00 g/mol


CO2                 1C ×    12.01 g/mol  = 12.01 g/mol

                        2O ×   16.00 g/mol  = 32.00 g/mol

                                                SUM   = 44.01 g/mol


H2O                 2H ×    1.008 g/mol  = 2.016 g/mol

                        1O ×   16.00 g/mol  = 16.00 g/mol

                                                SUM   = 18.016 g/mol

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Problem Details

For the following equation:

2CH3CH3 + 7O2 → 4CO2 + 6H2O

Answer these questions:

a) If 13.50g of CH3CH3 reacts with 2.00g of oxygen, which is the limiting reagent?

b) If 13.50g of CH3CH3 reacts with 2.00g of oxygen, calculate the number of g of water formed?

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Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.