# Problem: For the following equation:2CH3CH3 + 7O2 → 4CO2 + 6H2OAnswer these questions:a) If 13.50g of CH3CH3 reacts with 2.00g of oxygen, which is the limiting reagent?b) If 13.50g of CH3CH3 reacts with 2.00g of oxygen, calculate the number of g of water formed?

###### FREE Expert Solution

We are being asked to:

(a) determine the limiting reactant when 13.50 g of CH3CHreacts with 2.00 g of O2

(b) determine the amount of water formed when 13.50 g of CH3CHreacts with 2.00 g of O2

The molar masses of the involved compounds solved below before proceeding with further calculations.

CH3CH3           2C ×    12.01 g/mol  = 24.02 g/mol

6H ×    1.008 g/mol  = 6.048 g/mol

SUM   = 30.068 g/mol

O2                    2O ×   16.00 g/mol  = 32.00 g/mol

SUM   = 32.00 g/mol

CO2                 1C ×    12.01 g/mol  = 12.01 g/mol

2O ×   16.00 g/mol  = 32.00 g/mol

SUM   = 44.01 g/mol

H2O                 2H ×    1.008 g/mol  = 2.016 g/mol

1O ×   16.00 g/mol  = 16.00 g/mol

SUM   = 18.016 g/mol

###### Problem Details

For the following equation:

2CH3CH3 + 7O2 → 4CO2 + 6H2O