Problem: Hydrochloric acid HCl reacts with sodium carbonate Na 2CO3, forming sodium chloride NaCl, water H2O, and carbon dioxide CO2. This equation is balanced as written:2HCl(aq) + Na2CO3(aq) = 2NaCl(aq) + H2O(l) + CO2(g)A 581-mL sample of unknown HCl solution reacts completely with Na 2CO3 to form 15.1 g CO2-. What was the concentration of the HCl solution? Express the molar concentration numerically.

Determine the moles of CO₂ in 15.g of CO₂ and then use stoichiometry to find the moles of HCl reacted. Then divide this by the L of HCl provided

Step 1. Setup the dimensional analysis and list the necessary calculations

• The molar mass of CO₂ will appear as:

CO₂                      1 C x 12.01 g/mol = 12.01 g/mol

                              2 O x 16 g/mol = 32 g/mol

                                    Sum = 44.01 g/mol