Problem: Hydrochloric acid HCl reacts with sodium carbonate Na 2CO3, forming sodium chloride NaCl, water H2O, and carbon dioxide CO2. This equation is balanced as written:2HCl(aq) + Na2CO3(aq) = 2NaCl(aq) + H2O(l) + CO2(g)A 581-mL sample of unknown HCl solution reacts completely with Na 2CO3 to form 15.1 g CO2-. What was the concentration of the HCl solution? Express the molar concentration numerically.

FREE Expert Solution

Determine the moles of CO2 in 15.g of CO2 and then use stoichiometry to find the moles of HCl reacted. Then divide this by the L of HCl provided

Step 1. Setup the dimensional analysis and list the necessary calculations

  • The molar mass of CO2 will appear as:

CO                     1 C x 12.01 g/mol = 12.01 g/mol

                              2 O x 16 g/mol = 32 g/mol

                                    Sum = 44.01 g/mol

View Complete Written Solution
Problem Details

Hydrochloric acid HCl reacts with sodium carbonate Na 2CO3, forming sodium chloride NaCl, water H2O, and carbon dioxide CO2. This equation is balanced as written:

2HCl(aq) + Na2CO3(aq) = 2NaCl(aq) + H2O(l) + CO2(g)

A 581-mL sample of unknown HCl solution reacts completely with Na 2CO3 to form 15.1 g CO2-. What was the concentration of the HCl solution? Express the molar concentration numerically.