Problem: Balance the following reaction:NO2-(aq) + Cr2O72-(aq) → Cr3+(aq) + NO3-(aq)  (acidic solution)

FREE Expert Solution

We are being asked to balance the given oxidation-reduction reaction. The reaction is under acidic conditionsWhen balancing redox reactions under acidic conditions, we will follow the following steps.

Step 1: Separate the whole reaction into two half-reactions

Step 2: Balance the non-hydrogen and non-oxygen elements first

Step 3: Balance oxygen by adding H2O to the side that needs oxygen (1 O: 1 H2O)

Step 4: Balance hydrogen by adding H+ to the side that needs hydrogen (1 H: 1 H+)

Step 5: Balance the charges: add electrons to the more positive side (or less negative side)

Step 6: Balance electrons on the two half-reactions

Step 7: Get the overall reaction by adding the two reactions.


Balance the redox reaction under acidic conditions:

NO2-(aq) + Cr2O72-(aq) → Cr3+(aq) + NO3-(aq)


*Before balancing the redox reaction:

ignore H+, OH-, and H2O in the starting reaction


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Problem Details

Balance the following reaction:

NO2-(aq) + Cr2O72-(aq) → Cr3+(aq) + NO3-(aq)  (acidic solution)