Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Draw the potential energy diagram for the combustion of propane:C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g) + 2219.9 kJ


Draw the potential energy diagram for the combustion of propane:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g) + 2219.9 kJ


We have to draw a potential energy diagram for the given reaction:

C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g) + 2219.9 kJ

This reaction is the combustion of propane (C3H8).

Combustion is a reaction where a compound burns in oxygen to produce carbon dioxide (CO2) and water (H2O).

To draw the potential energy diagram for this reaction, we have to first determine whether this reaction is endothermic or exothermic.

This is because endothermic and exothermic reactions have different potential energy diagrams.

Let’s start by analyzing the equation.

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