We have to determine the energy of the photon emitted when an electron in a hydrogen atom relaxes from n=5 to n=3.

The energy change that is accompanied when an electron falls from a higher energy level to a lower energy level is given by the **Bohr equation**.

$\overline{){\u2206}{\mathrm{E}}{}{=}{}{-}{{\mathrm{R}}}_{{\mathrm{H}}}\left(\frac{1}{{\mathrm{n}}_{\mathrm{final}}^{2}}-\frac{1}{{\mathrm{n}}_{\mathrm{initial}}^{2}}\right)}$

Where, R_{H} = Rydberg constant = 2.18x10^{-18} J

Calculate the energy of a photon emitted when an electron in a hydrogen atom relaxes from n = 5 to n = 3?

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