Before balancing the chemical reaction, let’s first write the chemical formula of the compounds involved in the reaction.
Lead (II) nitrate
▪ Lead (II) → +2 charge → Pb+
▪ Nitrate ion → -1 charge → NO3-
▪ Combine both ions, the charge of the ion goes to the subscript of the counterion
Lead (II) nitrate: Pb(NO3)2 (aq)
How do you write the reaction of lead(II) nitrate (aq) with sodium iodide (aq) to form lead (II) iodide precipitate and sodium nitrate solution?