Problem: For a particular reaction, ΔH = 120.5 kJ and ΔS = 758.2 J/K. What is ΔG for this reaction at 298 K?

FREE Expert Solution

Recall that the standard Gibbs free energy change of a reaction (ΔG˚rxn) is given by the following equation:

Grxn°=Hrxn°-TSrxn°


We know that for a particular reaction, ΔH = 120.5 kJ and ΔS = 758.2 J/K at T = 298 K.  

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For a particular reaction, ΔH = 120.5 kJ and ΔS = 758.2 J/K. What is ΔG for this reaction at 298 K?