# Problem: For a particular reaction, ΔH = 120.5 kJ and ΔS = 758.2 J/K. What is ΔG for this reaction at 298 K?

###### FREE Expert Solution

Recall that the standard Gibbs free energy change of a reaction (ΔG˚rxn) is given by the following equation:

$\overline{){\mathbf{∆}}{{\mathbf{G}}}_{\mathbf{r}\mathbf{x}\mathbf{n}}{\mathbf{°}}{\mathbf{=}}{\mathbf{∆}}{{\mathbf{H}}}_{\mathbf{r}\mathbf{x}\mathbf{n}}{\mathbf{°}}{\mathbf{-}}{\mathbf{T}}{\mathbf{∆}}{{\mathbf{S}}}_{\mathbf{r}\mathbf{x}\mathbf{n}}{\mathbf{°}}}$

We know that for a particular reaction, ΔH = 120.5 kJ and ΔS = 758.2 J/K at T = 298 K.

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###### Problem Details

For a particular reaction, ΔH = 120.5 kJ and ΔS = 758.2 J/K. What is ΔG for this reaction at 298 K?

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