Problem: What is the rate law for the following mechanism in terms of the overall rate constant k? Step 1: A + B ↔ C (fast) Step 2: B + C → D (slow)

FREE Expert Solution

We’re asked to determine the overall rate constant K for the given two steps mechanism.

When a reaction mechanism is given, the rate law will depend on reactants and products in the slow step.

Rate law only involves the reactants
 The coefficients of the reactants in the slow step are the order of the reaction with respect to that reactant
 Rate Law has a general form of:

Rate Law=kXaYb

Where

k = rate constant

X & Y = reactants

a & b = reactant orders


 The equilibrium constant has a general form of:

 Kr=productsreactants


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Problem Details

What is the rate law for the following mechanism in terms of the overall rate constant k? 

Step 1: A + B ↔ C (fast) 

Step 2: B + C → D (slow)

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Reaction Mechanism concept. If you need more Reaction Mechanism practice, you can also practice Reaction Mechanism practice problems.