We must first convert from a word equation to a symbol equation before writing the balanced reaction equation:
Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium Nitrate
In lead (II) ion, the roman numeral II corresponds to a +2 charge, whilst the nitrate ion is NO3−. To balance the charges, we require two nitrate ions per lead (II) ion, and so lead (II) nitrate is Pb(NO3)2.
The potassium ion is K+ has charge of +1 as it is from group 1A and the iodide ion has a charge of -1 because it is from group 7A, the two charges balance in a 1:1 ratio, so potassium iodide is simply KI.
In lead (II) iodide, the lead is Pb2+ and the iodide is I− and the charges balance in a 1:2 ratios, so the formula is PbI2.
Lead (II) nitrate reacts with potassium iodide to form lead (II) iodide and potassium nitrate. Write the balanced equation for this.
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