A) We’re being asked to predict the sign of the entropy change (ΔS) for the given reaction. Recall that if:
• ΔS > 0 or ΔS = (+); entropy is increased
• ΔS < 0 or ΔS = (–); entropy is decreased
ΔG° = ΔH° - T ΔS°
For the reaction
Cu2O(s) + C(s) → 2Cu(s) + CO(g)
a. would you expect a positive or negative change in entropy? Explain your answer.
b. If this reaction is exothermic, under what temperature conditions (low, high or any) will this reaction be spontaneous?
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