Problem: ΔG° = ΔH° - T ΔS°For the reaction Cu2O(s) + C(s) → 2Cu(s) + CO(g)a. would you expect a positive or negative change in entropy? Explain your answer. b. If this reaction is exothermic, under what temperature conditions (low, high or any) will this reaction be spontaneous?

FREE Expert Solution

A) We’re being asked to predict the sign of the entropy change (ΔS) for the given reaction. Recall that if:

• ΔS > 0 or ΔS = (+); entropy is increased

• ΔS < 0 or ΔS = (–); entropy is decreased

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Problem Details

ΔG° = ΔH° - T ΔS°

For the reaction 

Cu2O(s) + C(s) → 2Cu(s) + CO(g)

a. would you expect a positive or negative change in entropy? Explain your answer. 

b. If this reaction is exothermic, under what temperature conditions (low, high or any) will this reaction be spontaneous?

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