We have to calculate the time required to deposit 7.10 g of lead metal from a solution containing Pb(NO3)2.
Pb2+ has a +2 charge, so it requires 2 electrons to discharge completely and deposit as a metal.
Pb2+(aq) + 2e- → Pb(s)
A current of 3.07 A is passed through a Pb(NO3)2 solution. How long (in hours) would this current have to be applied to plate out 7.10 g of lead?
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