We have to calculate the amount of gallium metal that is deposited on the cathode through electrolysis of a solution containing Ga3+ ions.
Ga3+ has a +3 charge, so it requires 3 electrons to discharge completely and deposit as a metal.
Ga3+(aq) + 3e- → Ga(s)
Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate the amount of Ga(s) that can be deposited from a Ga(III) solution by a current of 0.730 A that flows for 40.0 min.
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