Problem: Balance the equation and solve the following questions.CH3CH3 + O2 → CO2 + H2Oa) How many moles of CH3CH3 are in 13.50g of CH3CH3b) If 13.50g of CH3CH3 react with excess oxygen, how many g of water will be formed?c) If 13.50g of CH3CH3 react with excess oxygen how many moles of CO 2 will be formed?d) If 13.50g of CH3CH3 react with excess oxygen how many molecules of CO 2 will be formed?

FREE Expert Solution

We are being asked to balance the equation first in order to perform the succeeding stoichiometric calculations.

Before balancing the chemical reaction, let’s first write the chemical formula of each of the compounds involved in the reaction.


Reactants:

Ethane (gas)

Ethane: CH3CH3(g)

Oxygen (gas)

▪ oxygen gas is the natural state of oxygen

▪ natural state of oxygen O2(g)

Products:

Carbon dioxide (gas)  CO2(g)

Water vapor (gas)  H2O(g)


Unbalanced Chemical Reaction: CH3CH3(g) + O2(g)  CO2(g) + H2O(g)

To make it easier for us to balance the equation, we can denote ethane (CH3CH3as C2H6.

Balancing the chemical reaction: 

1. Balance the non oxygen and non hydrogen elements first:C

C2H6(g) + O2(g) 2 CO2(g) + H2O(g)

2. Balance Hydrogen

C2H6(g) + O2(g) 2 CO2(g) + 3 H2O(g) 

3. Balance Oxygen

C2H6(g)+7/2O2(g) 2 CO2(g) + 3 H2O(g) 

4. Make sure that all the coefficients are whole numbers

[ C2H6(g) + 7/2 O2(g)  2 CO2(g) + 3 H2O(g)] x 2

 2 C2H6(g) + O2(g)  4 CO2(g) + 6 H2O(g)

Balanced Reaction Equation:

2 CH3CH3(g)7 O2(g) 4 CO2(g)6 H2O(g)


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Problem Details

Balance the equation and solve the following questions.

CH3CH3 + O2 → CO2 + H2O

a) How many moles of CH3CH3 are in 13.50g of CH3CH3

b) If 13.50g of CH3CH3 react with excess oxygen, how many g of water will be formed?

c) If 13.50g of CH3CH3 react with excess oxygen how many moles of CO 2 will be formed?

d) If 13.50g of CH3CH3 react with excess oxygen how many molecules of CO 2 will be formed?

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