Problem: The concentration of iodide ions in a 0.193 M solution of barium iodide is __________.a. 0.193 Mb. 0.386 Mc. 0.0965 Md. 0.579 Me. 0.0643 M

FREE Expert Solution

We have to determine the concentration of iodide ions in a 0.193 M solution of barium iodide.

Barium iodide is made up of barium and iodide.

Barium is a group 2A metal which forms a cation with a charge of +2: Ba2+

Iodine is a group 7A nonmetal which forms an anion with a charge of -1: I-

To make a formula for the compound, we have to cross multiply the charges.

The formula is: BaI2

Barium iodide dissociates into its ions in a solution.

BaI2(aq) à Ba2+(aq) + 2 I-(aq)

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Problem Details

The concentration of iodide ions in a 0.193 M solution of barium iodide is __________.

a. 0.193 M

b. 0.386 M

c. 0.0965 M

d. 0.579 M

e. 0.0643 M

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