Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction isSO42- (aq) + Sn2+ (aq) → H2SO3 (aq) + Sn4+ (aq)Sicne this reaction takes place in acidic solut

Problem

In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is

SO42- (aq) + Sn2+ (aq) → H2SO(aq) + Sn4+ (aq)

Sicne this reaction takes place in acidic solution, H2O (l) and H+ (aq) will be involved in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation:

SO42- (aq) + Sn2+ (aq) + ___ → H2SO(aq) + Sn4+ (aq) + ___

What are the coefficients of the reactants and products in the balaced equation above? Remember to include H2O (l) and H+ (aq) in the appropriate blanks. Your answer should have six terms.

Solution

We have to balance the given redox equation by using H2O(l) and H+(aq) and determine their coefficients in the balanced chemical equation.

We will start by splitting the equation into two half-reactions and then determine which halves are reduction and oxidation halves.

Sn2+(aq) → Sn4+(aq)

Recall that the charge on a metal cation is its oxidation state.

The oxidation state of Sn is increasing from +2 to +4 therefore, this is the oxidation half-reaction.

SO42-(aq) → H2SO3(aq)

Since we have already determined the oxidation half-reaction, this one must be the reduction half-reaction.

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