We´re asked to determine the limiting reactant in the reaction of 0.893 moles of NO with 0.519 moles of O2, and the number of moles of NO2 produced.
Consider that the limiting reactant is the one that’s consumed completely in the reaction and forms the less amount of product, and the excess reactant is the one that remains after the reaction is completed and forms the most amount of product.
The problem can be solved in 2 steps:
Step 1: Calculate the number of moles of NO2 produced by each reactant.
Nitric axide (NO) reacts with oxygen gas to form nitrogen dioxide (NO 2) a dark brown gas:
2NO(g) + O2(g) → 2NO2(g)
In one experiment. 0.893 mol of NO is mixed with 0.519 mol of O 2. Determnine which of the two reactants is the limiting reactant. Calculate also the number if moles NO2 produced.
(A) Limiting reactant
(B) moles of NO2 produced
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.