Problem: 1. Consider the following two substances and their vapor pressures at 298 K.Substance Vapor Pressure (mmHg)A 275B 459Based on this information compare the characteristcs of the two substances.weaker intermolecular forcehigher boiling pointhigher heat of vaporizationexist in gaseous phase at 300 K2. The vapor pressure of dichloromethane, CH 2Cl2, at 0°C is 134 mmHg. The normal boiling point of dichloromethane is 40. Calculate its molar heat of vaporization?

FREE Expert Solution

1. Substance A has a lower vapor pressure than substance B. A lower vapor pressure means stronger intermolecular forces because the liquid molecules do not easily escape to the gaseous phase. Therefore, substance A has a stronger intermolecular force and substance B has a weaker intermolecular force.


Since Substance A has a stronger intermolecular force, it also has a higher boiling point and higher heat of vaporization. This is because more energy (in the form of heat) is needed to bring the liquid to boil and to vaporize the liquid


98% (474 ratings)
View Complete Written Solution
Problem Details

1. Consider the following two substances and their vapor pressures at 298 K.

Substance Vapor Pressure (mmHg)

A 275

B 459

Based on this information compare the characteristcs of the two substances.

weaker intermolecular force

higher boiling point

higher heat of vaporization

exist in gaseous phase at 300 K

2. The vapor pressure of dichloromethane, CH 2Cl2, at 0°C is 134 mmHg. The normal boiling point of dichloromethane is 40. Calculate its molar heat of vaporization?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Clausius-Clapeyron Equation concept. You can view video lessons to learn Clausius-Clapeyron Equation. Or if you need more Clausius-Clapeyron Equation practice, you can also practice Clausius-Clapeyron Equation practice problems.