We must draw the Lewis structure for HNO3. We first need to determine the total number of valence electrons present in the molecule:
Group Valence Electrons
H 1A 1 × 1 e– = 1 e–
N 5A 1 x 5 e- = 5 e-
O 6A 3 × 6 e– = 18 e–
Total: 24 valence e–
Consider the Lewis structure for the nitric acid molecule, HNO 3, and select the false statement.
a. More than one resonance structure is required.
b. The N–O bond order is 4/3.
c. In water, the H–N bond is broken to form H 3O+.
d. The formal charge on nitrogen is +1.
e. The oxidation state of nitrogen is +5.
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