NaOH is a strong base while HCl is a strong acid. No ICE or ICF chart is needed.
A. First, calculate the amount of acid and base that will react
molarity (volume) → moles
*convert mL to L → 1 mL = 10-3 L
Calculate the pH of the resulting solution if 27.0 ml of 0.270 M HCl is added to
a) 32.0 ml of 0.270 M NaOH(aq)
b) 37.0 ml of 0.320 M NaOH(aq)
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