# Problem: Enter formulas for these ionic compounds. copper(I) bromide copper(II) bromide iron(III) bromide lead(IV) bromide copper(I) oxide copper(II) oxide iron(III) oxide lead(IV) oxide

###### FREE Expert Solution

An ionic compound involves the bond between a cation (positive ion) and an anion (negative ion)

Metals lose electrons to be positive ions (cations), whereas non-metals gain electrons to become negative ions (anions)

In writing the molecular formula of ionic compounds:

• The roman numeral after the name of the transition metal indicates its charge

Determine the charge of the anion or polyatomic anion

In this case, the ionic compounds have bromide or oxide its anion.

The suffix ‘ide indicates that the ion is anionic.

• To write the complete molecular formula, simply crisscross the charges of the two atoms.

###### Problem Details

Enter formulas for these ionic compounds.

copper(I) bromide

copper(II) bromide

iron(III) bromide

copper(I) oxide

copper(II) oxide

iron(III) oxide