We’re being asked to calculate the mass of CaCO3 that will react with 72.5 mL of a 0.250 M solution of HCl.
V HCl (M HCl) →mol of HCl (mole –to-mole comparison) →mol CaCO3 (Molar Mass CaCO3) →mass CaCO3
• molarity (volume) → moles
*convert volumes from mL to L → 1 mL = 10-3 L
GIven the balanced equation:
CaCO3 (s) + 2HCl (aq) → CaCl 2 (aq) + H2O (l) + CO 2 (g)
Select all statements that correctly describe how to calculate the mass of CaCO 3 that will react with 72.5 mL of a 0.250 M solution of HCl (The molar mass of CaCO3 = 100.09 g/mol).
SELECT ALL THAT APPLY.
-3.62 x 102 moles of CaCO3 will react
-0.906 g of CaCO3 will react
-0.290 mol of HCl are used in this reaction
The conversion factor (0.250 mol HCl)/(1L) will be used as written in the calculation.
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