# Problem: GIven the balanced equation: CaCO3 (s) + 2HCl (aq) → CaCl 2 (aq) + H2O (l) + CO 2 (g) Select all statements that correctly describe how to calculate the mass of CaCO  3 that will react with 72.5 mL of a 0.250 M solution of HCl (The molar mass of CaCO3 = 100.09 g/mol). SELECT ALL THAT APPLY. -3.62 x 102 moles of CaCO3 will react -0.906 g of CaCO3 will react -0.290 mol of HCl are used in this reaction The conversion factor (0.250 mol HCl)/(1L) will be used as written in the calculation.

###### FREE Expert Solution

We’re being asked to calculate the mass of CaCO3 that will react with 72.5 mL of a 0.250 M solution of HCl.

V HCl (M HCl) →mol of HCl (mole –to-mole comparison) →mol CaCO(Molar Mass CaCO3) →mass CaCO3

• molarity (volume) → moles

Recall:

*convert volumes from mL to L → 1 mL = 10-3 L

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###### Problem Details

GIven the balanced equation:

CaCO3 (s) + 2HCl (aq) → CaCl 2 (aq) + H2O (l) + CO 2 (g)

Select all statements that correctly describe how to calculate the mass of CaCO  3 that will react with 72.5 mL of a 0.250 M solution of HCl (The molar mass of CaCO3 = 100.09 g/mol).

SELECT ALL THAT APPLY.

-3.62 x 102 moles of CaCO3 will react

-0.906 g of CaCO3 will react

-0.290 mol of HCl are used in this reaction

The conversion factor (0.250 mol HCl)/(1L) will be used as written in the calculation.

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