We are provided with a complete and a net ionic equation for the reaction that takes place between NaCl and AgNO_{3} and we have to determine the number of moles and mass of NaCl.

We will solve this problem through these steps:

- Find the number of moles of AgNO
_{3}using the formula for molarity. - Make a mole-to-mole comparison using the balanced chemical equation to find the number of moles of NaCl in titrated samples.
- Convert the moles of NaCl to mass (g) using the formula mass of NaCl.

Fully balanced equation: AgNO_{3} + NaCl → AgCl + NaNO _{3}

Net ionic equation: Ag^{+} + Cl ^{-} → AgCl

Volume of (.0100 M) AgNO_{3} to titrate bay water samples:

March: 7.3 mL

April: 4.46 mL

1) Using the balance equation, calculate the average number of moles of NaCl in each of the titrated samples.

2) Calculate the average number of grams of NaCl in each titrated samples.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Solution Stoichiometry concept. You can view video lessons to learn Solution Stoichiometry. Or if you need more Solution Stoichiometry practice, you can also practice Solution Stoichiometry practice problems.