Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The Ksp of calcium carbonate, CaCO3, is 3.36 x 10-9. Calculate the solubility of this compound in g/L.

Problem

The Ksp of calcium carbonate, CaCO3, is 3.36 x 10-9. Calculate the solubility of this compound in g/L.

Solution

For this problem, we´re asked to calculate the solubility of this compound in g/L based on its Ksp of 3.36x10-9.


The compound is ionic and is a little soluble in water, with a dissociation as follows:

The Calcium ion Ca2+ is in group 2A and has a charge of +2. Carbonate then has a charge of -2:

CaCO3(s)  Ca2+(aq) + CO32-(aq)


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