The standard free energy of formation of CS 2 (l) is 65.27 kJ⋅mol −1 at 298 K. This means that at 298 K
a) CS2 (l) will not spontaneously form C (s) + 2 S (s).
b) CS2 (l) is thermodynamically unstable.
c) CS2 (l) is thermodynamically stable.
d) No catalyst can be found to decompose CS 2 (l) into its elements.
e) CS2 (l) has a negative entropy.
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