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Problem: The standard free energy of formation of CS 2 (l) is 65.27 kJ⋅mol −1 at 298 K. This means that at 298 K a) CS2 (l) will not spontaneously form C (s) + 2 S (s). b) CS2 (l) is thermodynamically unstable. c) CS2 (l) is thermodynamically stable. d) No catalyst can be found to decompose CS 2 (l) into its elements. e) CS2 (l) has a negative entropy.

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The standard free energy of formation of CS (l) is 65.27 kJ⋅mol −1 at 298 K. This means that at 298 K

a) CS(l) will not spontaneously form C (s) + 2 S (s).

b) CS(l) is thermodynamically unstable.

c) CS(l) is thermodynamically stable.

d) No catalyst can be found to decompose CS (l) into its elements.

e) CS(l) has a negative entropy.

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