# Problem: What is the nuclear binding energy of a lithium-7 nucleus in units of kJ/mol and eV/nucleus? (Mass of a lithium-7 atom = 7.016003 amu.)

###### FREE Expert Solution

First, calculate mass defect:

Li–7 (atomic mass = 7.016003 amu)

Atomic number→ 3 → 3 protons

Mass number → 7

Neutrons → 7-3 = 4

Mass values needed:

Proton = 1.007277 amu

electron = 0.000548597 amu

neutron = 1.008665 amu

Lithium = 7.016003 amu

Calculate mass defect:

Δm = 0.042105 amu

Substitute the equation below:

1 amu c2 = 931.49 MeV

E = 3.92 x 107  eV/nucleus

Convert to kJ/mol:

###### Problem Details

What is the nuclear binding energy of a lithium-7 nucleus in units of kJ/mol and eV/nucleus? (Mass of a lithium-7 atom = 7.016003 amu.)

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Ratliff's class at USF.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.