Ch.19 - Nuclear ChemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Radon-222 decays to a stable nucleus by a series of three alpha emissions and two beta emissions.What is the stable nucleus that is formed?

Solution: Radon-222 decays to a stable nucleus by a series of three alpha emissions and two beta emissions.What is the stable nucleus that is formed?

Problem

Radon-222 decays to a stable nucleus by a series of three alpha emissions and two beta emissions.

What is the stable nucleus that is formed?

Solution

We are asked to determine a stable nucleus that is formed when radon-222 undergoes a series of three alpha emissions and two beta emissions.

For this item, we need to follow the steps below:

  • Step 1. Write the chemical reaction for the series of emissions.
  • Step 2. Calculate the mass number, Z, and the atomic number, A, for the resulting nuclei.
  • Step 3. Find the stable nuclei in the periodic table based on the atomic number and mass number.
Solution BlurView Complete Written Solution