# Problem: You may want to reference (Pages 920 - 922)Section 21.6 while completing this problemHow much energy must be supplied to break a single aluminum-27 nucleus into separated protons and neutrons if an aluminum-27 atom has a mass of 26.9815386 amu? How much energy is required for 100.0 g of aluminum-27? (The mass of an electron is 5.485799 10-4 amu, the mass of a proton is 1.0072765 amu, and the mass of a neutron is 1.0086649 amu.)

###### FREE Expert Solution

For 27Al:

Atomic number = number or protons = 13

Atomic mass = 27 amu

27 = 13 + # of neutrons

# of neutrons = 27-13

# of neutrons = 14

The nuclear reaction is:

(1): Calculate the mass defect (Δm).

$\overline{){\mathbf{∆}}{\mathbf{m}}{\mathbf{=}}{\mathbf{p}}{\mathbf{r}}{\mathbf{o}}{\mathbf{d}}{\mathbf{u}}{\mathbf{c}}{\mathbf{t}}{\mathbf{s}}{\mathbf{-}}{\mathbf{r}}{\mathbf{e}}{\mathbf{a}}{\mathbf{c}}{\mathbf{t}}{\mathbf{a}}{\mathbf{n}}{\mathbf{t}}{\mathbf{s}}}$

1 amu = 1.6606x10-27 kg

Δm = 3.892x10-28 kg

(2) Calculate the energy used (E).

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###### Problem Details

You may want to reference (Pages 920 - 922)Section 21.6 while completing this problem

How much energy must be supplied to break a single aluminum-27 nucleus into separated protons and neutrons if an aluminum-27 atom has a mass of 26.9815386 amu? How much energy is required for 100.0 g of aluminum-27? (The mass of an electron is 5.485799 10-4 amu, the mass of a proton is 1.0072765 amu, and the mass of a neutron is 1.0086649 amu.)