Atomic number = number or protons = 13
Atomic mass = 27 amu
27 = 13 + # of neutrons
# of neutrons = 27-13
# of neutrons = 14
The nuclear reaction is:
(1): Calculate the mass defect (Δm).
1 amu = 1.6606x10-27 kg
Δm = 3.892x10-28 kg
(2) Calculate the energy used (E).
You may want to reference (Pages 920 - 922)Section 21.6 while completing this problem
How much energy must be supplied to break a single aluminum-27 nucleus into separated protons and neutrons if an aluminum-27 atom has a mass of 26.9815386 amu? How much energy is required for 100.0 g of aluminum-27? (The mass of an electron is 5.485799 10-4 amu, the mass of a proton is 1.0072765 amu, and the mass of a neutron is 1.0086649 amu.)
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Daubenmire's class at LUC.