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Gibbs Free Energy

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Spontaneous Reaction	10 mins	0 completed	Learn
First Law of Thermodynamics	6 mins	0 completed	Learn Summary
Entropy	58 mins	0 completed	Learn Summary
Gibbs Free Energy	30 mins	0 completed	Learn

Additional Practice
Second and Third Laws of Thermodynamics
Boltzmann Equation

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Solution: For the reaction NH4Cl (s) → NH3 (g) + HCl (g) ΔH ° = +176 kJ and ΔG ° = +91.2 kJ at 298 K. What is the value of ΔG at 1000 K? a) -109 kJ b) -64 kJ c) +64 kJ d) +109 kJ

Name: For the reaction NH4Cl (s) → NH3 (g) + HCl (g) ΔH ° = +176 kJ and ΔG ° = +91.2 kJ at 298 K. What is the value of ΔG at 1000 K? a) -109 kJ b) -64 kJ c) +64 kJ d) +109 kJ
Uploaded: 2016-11-23T10:31:05.000-05:00
Duration: 4 min 44 s
Description: Watch the video solution for the question: For the reaction NH4Cl (s) → NH3 (g) + HCl (g) ΔH ° = +176 kJ and ΔG ° = +91.2 kJ at 298 K. What is the value of ΔG at 1000 K? a) -109 kJ b) -64 kJ c) +64 kJ d) +109 kJ

Problem

For the reaction

NH₄Cl (s) → NH₃(g) + HCl (g)

ΔH ° = +176 kJ and ΔG ° = +91.2 kJ at 298 K. What is the value of ΔG at 1000 K?

a) -109 kJ

b) -64 kJ

c) +64 kJ

d) +109 kJ

Gibbs Free Energy

Solution: For the reaction NH4Cl (s) → NH3 (g) + HCl (g) ΔH ° = +176 kJ and ΔG ° = +91.2 kJ at 298 K. What is the value of ΔG at 1000 K? a) -109 kJ b) -64 kJ c) +64 kJ d) +109 kJ

Problem

Practice Problems