Problem: The half-life of 232Th is 1.4 x 1010 yr. Find the number of disintegrations per hour emitted by 1.0 mol of 232Th. (Note: 1 year = 365.24 days)

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FREE Expert Solution

Step 1: Convert the half-life from year to hour.

t12=1.4×1010 yr×365.24 days1 yr×24 hr1 day

t1/2 = 1.2272×1014 hr


Step 2: Calculate rate constant, k.

t12=ln 2kk=ln 2t12k=ln 21.2272×1014 hr

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Problem Details

The half-life of 232Th is 1.4 x 1010 yr. Find the number of disintegrations per hour emitted by 1.0 mol of 232Th. (Note: 1 year = 365.24 days)