We’re being asked to determine the particle that is used to bombard ^{238}U to produce ^{247}Es and five neutrons:

The reaction ca be written as:

${}_{\mathbf{92}}{}^{\mathbf{238}}\mathbf{U}\mathbf{}\mathbf{+}{\mathbf{?}}\mathbf{}\mathbf{\to}\mathbf{5}\mathbf{}{}_{\mathbf{0}}{}^{\mathbf{1}}\mathbf{n}\mathbf{}\mathbf{+}\mathbf{}{}_{\mathbf{99}}{}^{\mathbf{247}}\mathbf{Es}$

**The numbers written in below the mass numbers are the atomic numbers of each element and can be found on the periodic table.*

**Nuclear Fission **is the splitting of a heavy nucleus to form two or lighter ones.

Heavy (large atomic mass) elements undergo **radioactive reactions** (nuclear reactions) in order to increase the stability of their nuclei.

**The particle in the reaction can be represented as:**

The nuclide ^{247} Es can be made by bombardment of ^{238} U in a reaction that emits five neutrons.

Identify the bombarding particle.

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