🤓 Based on our data, we think this question is relevant for Professor Porter's class at IUPUI.

We’re being asked to calculate the energy produced for the following nuclear reaction:

${}_{\mathbf{92}}{}^{\mathbf{235}}\mathbf{U}\mathbf{+}{}_{\mathbf{0}}{}^{\mathbf{1}}\mathbf{n}\mathbf{\to}{}_{\mathbf{52}}{}^{\mathbf{137}}\mathbf{Te}\mathbf{+}{}_{\mathbf{40}}{}^{\mathbf{97}}\mathbf{Zr}\mathbf{+}\mathbf{2}{}_{\mathbf{0}}{}^{\mathbf{1}}\mathbf{n}$

To calculate the energy released for the reaction, we’re going to use the following steps:

*Step 1**: Calculate the mass defect (Δm).***Step 2**: Calculate the mass defect (Δm) in kg.**Step 3**: Calculate the energy released (E).

**Step 1: Calculate the mass defect (Δm).**

**Given:**

Calculate the quantity of energy produced per mole of U-235 (atomic mass = 235.043922 amu) for the neutron-induced fission of U-235 to produce Te-137 (atomic mass = 136.9253 amu) and Zr-97 (atomic mass = 96.910950 amu). (*Note*: the products produced will include two neutrons.)