Problem: The standard potential for the reduction of AgSCN(s) is +0.09 V.AgSCN(s) + e-  →  Ag(s) + SCN- (aq).Using this value and the electrode potential for Ag+ (aq), calculate the Ksp for AgSCN.Ag+(aq) + e-  →  Ag(s) Eo= +0.80 V

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FREE Expert Solution

We are asked to find the Ksp for AgSCN.


E°cell =0.0592 VnlogK
cell = standard cell potential
n = number of e- transferred
Q= reaction quotient = [products]/[reactants] 


 We have to determine the E°cell first and as well as the anode (oxidation) and cathode (reduction) in the concentration cell and the number of electrons transferred (n).


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Problem Details

The standard potential for the reduction of AgSCN(s) is +0.09 V.
AgSCN(s) + e-  →  Ag(s) + SCN- (aq).


Using this value and the electrode potential for Ag+ (aq), calculate the Ksp for AgSCN.

Ag+(aq) + e-  →  Ag(s) Eo= +0.80 V


Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Cell Potential concept. If you need more Cell Potential practice, you can also practice Cell Potential practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Casey's class at UNR.