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We are asked to find the Ksp for AgSCN.
E°cell = standard cell potential
n = number of e- transferred
Q= reaction quotient = [products]/[reactants]
We have to determine the E°cell first and as well as the anode (oxidation) and cathode (reduction) in the concentration cell and the number of electrons transferred (n).
The standard potential for the reduction of AgSCN(s) is +0.09 V.
AgSCN(s) + e- → Ag(s) + SCN- (aq).
Using this value and the electrode potential for Ag+ (aq), calculate the Ksp for AgSCN.
Ag+(aq) + e- → Ag(s) Eo= +0.80 V
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
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Based on our data, we think this problem is relevant for Professor Casey's class at UNR.