# Problem: The standard potential for the reduction of AgSCN(s) is +0.09 V.AgSCN(s) + e-  →  Ag(s) + SCN- (aq).Using this value and the electrode potential for Ag+ (aq), calculate the Ksp for AgSCN.Ag+(aq) + e-  →  Ag(s) Eo= +0.80 V

###### FREE Expert Solution

We are asked to find the Ksp for AgSCN.

cell = standard cell potential
n = number of e- transferred
Q= reaction quotient = [products]/[reactants]

We have to determine the E°cell first and as well as the anode (oxidation) and cathode (reduction) in the concentration cell and the number of electrons transferred (n).

94% (329 ratings) ###### Problem Details

The standard potential for the reduction of AgSCN(s) is +0.09 V.
AgSCN(s) + e-  →  Ag(s) + SCN- (aq).

Using this value and the electrode potential for Ag+ (aq), calculate the Ksp for AgSCN.

Ag+(aq) + e-  →  Ag(s) Eo= +0.80 V

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