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Problem: Titration of an acidic solution of Na2C2O4 with KMnO4(aq).The balanced chemical equation for this reaction is:16 H+(aq) + 2 MnO4-(aq) + 5 C2O42-(aq)  →  2 Mn2+(aq) + 8 H2O(l) + 10 CO2(g)Which species is reduced in this reaction?

🤓 Based on our data, we think this question is relevant for Professor Lavis' class at Schoolcraft College.

FREE Expert Solution

We are asked to determine what species in the reaction is reduced.

To determine which element is reduced or oxidized, we must identify the changes in their oxidation states. Compare the oxidation number of the element on the reactant side and on the product side.

Remember the mnemonics:

Loss                Gain

Electrons         Electrons

Oxidation         Reduction


Reaction:

16 H+(aq) + 2 MnO4-(aq) + 5 C2O42-(aq)  →  2 Mn2+(aq) + 8 H2O(l) + 10 CO2(g)

Recall the rules for the oxidation states of some elements


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Problem Details

Titration of an acidic solution of Na2C2O4 with KMnO4(aq).

Photographs show a reaction of MnO4- with C2O42 -. a) A beaker contains a colorless solution of C2O42- (aqueous).  MnO4- (aqueous), which appears purple, is slowly added to the beaker.  The purple color of MnO4- disappears immediately as the reaction with C2O42- occurs. b) The solution in the beaker appears entirely purple. The purple color of MnO4- remains because C2O42- is completely consumed.

The balanced chemical equation for this reaction is:

16 H+(aq) + 2 MnO4-(aq) + 5 C2O42-(aq)  → Mn2+(aq) + 8 H2O(l) + 10 CO2(g)

Which species is reduced in this reaction?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Redox Reactions concept. If you need more Redox Reactions practice, you can also practice Redox Reactions practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Lavis' class at Schoolcraft College.