Chemistry Practice Problems Equivalence Point Practice Problems Solution: A saturated solution of Cd(OH)2 is shown in the mi...

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Solution: A saturated solution of Cd(OH)2 is shown in the middle beaker. If hydrochloric acid solution is added, the solubility of Cd(OH)2 will increase, causing additional solid to dissolve.Which of the two choices, Beaker A or Beaker B, accurately represents the solution after equilibrium is reestablished? (The water molecules and Cl- ions are omitted for clarity.)

Problem

A saturated solution of Cd(OH)2 is shown in the middle beaker. If hydrochloric acid solution is added, the solubility of Cd(OH)will increase, causing additional solid to dissolve.

A beaker contains a saturated solution with Cd2+ and OH- ions and Cd(OH)2 solid. Beaker A: Adding HCl leads to more Cd2+ and less precipitate. Beaker B: Adding HCl leads to more OH- and less precipitate.


Which of the two choices, Beaker A or Beaker B, accurately represents the solution after equilibrium is reestablished? (The water molecules and Cl- ions are omitted for clarity.)

Solution

We are asked which of the two choices, Beaker A or Beaker B, accurately represents the solution after equilibrium is reestablished. (The water molecules and Cl- ions are omitted for clarity.)


The dissolution of Cd(OH)in water can be represented by:

Cd(OH)2 (s) ⇌  Cd2+ (aq)+ OH-(aq)

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