# Problem: There are three voltaic cells. In each voltaic cell one half-cell contains a 1.0 M Fe(NO3)2(aq) solution with an Fe electrode. The contents of the other half-cells are as follows:Cell 1: a 1.0 M CuCl2(aq) solution with a Cu electrodeCell 2: a 1.0 M NiCl2(aq) solution with a Ni electrodeCell 3: a 1.0 M ZnCl2(aq) solution with a Zn electrodeIn which voltaic cell(s) does iron act as the anode?

###### FREE Expert Solution

• ↓ E° → oxidation → anode
• ↑ E° → reduction → cathode

Fe(NO3)2 Fe2+ + 2 NO3-

Fe2+(aq) + 2 e- → Fe(s)                     E° = –0.447 V → anode

Find the half-reaction with higher E° value than Fe2+/Fe:

CuCl2 Cu2+ + 2 Cl-

Cu2+(aq) + 2 e- → Cu(s)                     E° = 0.3419 V

NiCl2 Ni2+ + 2 Cl-

91% (311 ratings)
###### Problem Details

There are three voltaic cells. In each voltaic cell one half-cell contains a 1.0 M Fe(NO3)2(aq) solution with an Fe electrode. The contents of the other half-cells are as follows:

• Cell 1: a 1.0 M CuCl2(aq) solution with a Cu electrode
• Cell 2: a 1.0 M NiCl2(aq) solution with a Ni electrode
• Cell 3: a 1.0 M ZnCl2(aq) solution with a Zn electrode

In which voltaic cell(s) does iron act as the anode?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Galvanic Cell concept. You can view video lessons to learn Galvanic Cell. Or if you need more Galvanic Cell practice, you can also practice Galvanic Cell practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Bindell's class at UCF.