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NaHCO_{3}(s) ⇌ NaOH(s) + CO_{2}(g)

*solids are included in the K expression

*since gas is given we will use K_{p} and pressure

$\mathbf{K}\mathbf{=}\frac{\mathbf{products}}{\mathbf{reactants}}\phantom{\rule{0ex}{0ex}}\overline{){\mathbf{K}}_{\mathbf{p}}\mathbf{=}{\mathbf{P}}_{{\mathbf{CO}}_{\mathbf{2}}}}$

We can use the following equation to solve for ** ΔG˚_{rxn}**:

$\overline{){\mathbf{\Delta G}}{{\mathbf{\xb0}}}_{{\mathbf{rxn}}}{\mathbf{=}}{\mathbf{\Delta G}}{{\mathbf{\xb0}}}_{\mathbf{f}\mathbf{,}\mathbf{}\mathbf{prod}}{\mathbf{-}}{\mathbf{\Delta G}}{{\mathbf{\xb0}}}_{\mathbf{f}\mathbf{,}\mathbf{}\mathbf{react}}}$

The values for **ΔG˚ _{f}** can be looked up in textbooks or online:

Using data from Appendix C in the textbook, write the equilibrium-constant expression and calculate the value of the equilibrium constant and the free-energy change for these reactions at 298 K .

NaHCO_{3}(s) ⇌ NaOH(s) + CO_{2}(g)

What is the free-energy change for this reaction at 298 K?

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Based on our data, we think this problem is relevant for Professor Liwosz's class at UB.